Bitcoin Core  27.99.0 P2P Digital Currency
field_impl.h File Reference
`#include "field.h"`
`#include "util.h"`
`#include "field_10x26_impl.h"`
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## Functions

static SECP256K1_INLINE int secp256k1_fe_equal (const secp256k1_fe *a, const secp256k1_fe *b)

static int secp256k1_fe_sqrt (secp256k1_fe *SECP256K1_RESTRICT r, const secp256k1_fe *SECP256K1_RESTRICT a)

static void secp256k1_fe_verify (const secp256k1_fe *a)

static void secp256k1_fe_verify_magnitude (const secp256k1_fe *a, int m)

## ◆ secp256k1_fe_equal()

 static SECP256K1_INLINE int secp256k1_fe_equal ( const secp256k1_fe * a, const secp256k1_fe * b )
static

Definition at line 21 of file field_impl.h.

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## ◆ secp256k1_fe_sqrt()

 static int secp256k1_fe_sqrt ( secp256k1_fe *SECP256K1_RESTRICT r, const secp256k1_fe *SECP256K1_RESTRICT a )
static

Given that p is congruent to 3 mod 4, we can compute the square root of a mod p as the (p+1)/4'th power of a.

As (p+1)/4 is an even number, it will have the same result for a and for (-a). Only one of these two numbers actually has a square root however, so we test at the end by squaring and comparing to the input. Also because (p+1)/4 is an even number, the computed square root is itself always a square (a ** ((p+1)/4) is the square of a ** ((p+1)/8)).

The binary representation of (p + 1)/4 has 3 blocks of 1s, with lengths in { 2, 22, 223 }. Use an addition chain to calculate 2^n - 1 for each block: 1, [2], 3, 6, 9, 11, [22], 44, 88, 176, 220, [223]

Definition at line 33 of file field_impl.h.

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## ◆ secp256k1_fe_verify()

 static void secp256k1_fe_verify ( const secp256k1_fe * a )
static

Definition at line 145 of file field_impl.h.

## ◆ secp256k1_fe_verify_magnitude()

 static void secp256k1_fe_verify_magnitude ( const secp256k1_fe * a, int m )
static

Definition at line 146 of file field_impl.h.